Friday, April 29, 2016

Published April 29, 2016 by with 0 comment

UVA10163 : Last Digit -solution

#include<cstdio>
#include<math.h>
#include<string.h>
using namespace std;

int main()
{
    int a[21]={4,1,5,2,8,3,9,2,8,7,7,8,4,7,3,8,4,1,5,4,4};
    int a4[5]={0,4,8,2,6};
    char n[111];
    while (scanf("%s",n)!=EOF)
    {
        int l=strlen(n);
        if (l==1 && n[0]=='0') return 0;
        int d,r,ans;
        if (l==1) d=n[0]-48;
        else if (l==2) d=(n[0]-48)*10+n[1]-48;
        else d=(n[l-3]-48)*100+(n[l-2]-48)*10+n[l-1]-48;
        if (d==0)
        {
        printf("0\n");
        continue;
        }
        r=d/20;
        d=d%20;
        if (d==0) r--;
        r=r%5;
        ans=(a[d]+a4[r])%10;
        printf("%d\n",ans);
    }
    return 0;
}
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Thursday, April 28, 2016

Published April 28, 2016 by with 0 comment

UVA 944 : Happy numbers - solution

#include<bits/stdc++.h>
using namespace std;

int happy[410];
bool unhappy[410];
int digit_add(int n)
{
    int sum=0;
    while (n)
    {
        int a=n%10;
        sum+=a*a;
        n/=10;
    }
    return sum;
}

int ishappy(int n)
{
    bool visit[410];
    memset(visit,false,410);
    visit[n]=true;
    int count=0;
    while (1)
    {
        count++;
        n=digit_add(n);
        if (n==1) return count;
        if (happy[n]) return happy[n]+count;
        if (visit[n]) return 0;
        if (unhappy[n]) return 0;
        visit[n]=true;
    }
}

void preset()
{
    memset(happy, 0, 410);
    memset(unhappy,false,410);
    for (int i=1;i<410;i++)
    {
        int temp=ishappy(i);
        if (temp==0)
        for (int j=i;j<410;j*=10)
        unhappy[j]=true;
        else
        for (int j=i;j<410;j*=10)
        happy[j]=temp;
    }
    return;
}
int main()
{
    int l,h,t=0;
    preset();
    while (scanf("%d%d",&l,&h)!=EOF)
    {
        if (t) printf("\n");
        for (int i=l;i<=h;i++)
        {
            if (i==1)
            {
                printf("1 1\n");
                continue;
            }
            int n=digit_add(i);
            if (n==1) printf("%d 2\n",i);
            else if (happy[n])  printf("%d %d\n",i,happy[n]+2);
        }
        t=1;
    }
    return 0;
}
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Published April 28, 2016 by with 0 comment

UVA 10515 - Powers Et Al -solution

#include<cstdio>
#include<math.h>
#include<string.h>
using namespace std;

int main()
{
    char m[111],n[111];
    while (scanf("%s%s",m,n)!=EOF)
    {
        int lm=strlen(m);
        int ln=strlen(n);
        if (lm==1 && ln==1 && m[0]=='0' && n[0]=='0')
        return 0;
        if (ln==1&& n[0]=='0')
        {
            printf("1\n");
            continue;
        }
        int d=m[lm-1]-'0'; //last digit of m
        int cycle;
        if (d==0 || d==1||d==5 ||d==6)
        {
            printf("%d\n",d);
            continue;
        }
        else if (d==2|| d==3 || d==7 || d==8) cycle=4;
        else if (d==4 || d==9) cycle=2;
        int power;
        if (ln==1) power=(n[ln-1]-'0')%cycle;
        else
        power=((n[ln-2]-'0')*10+(n[ln-1]-'0'))%cycle;
        if (power==0) power=cycle;
        d=pow(d,power);
        d=d%10;
        printf("%d\n",d);
    }
    return 0;
}
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Published April 28, 2016 by with 0 comment

UVA 350. - Pseudo-Random Numbers. -solution

#include<cstdio>
using namespace std;

int main()
{
    int z,i,m,l,c=1;
    while (scanf("%d%d%d%d",&z,&i,&m,&l)==4)
    {
        if (!z && !i && !m && !l) return 0;
        int count=0;
        int L=(z*l+i)%m;
        l=L;
        do
        {
            L=(z*L+i)%m;
            count++;
        }while (L!=l);
        printf("Case %d: %d\n",c++,count);
    }
    return 0;
}
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Published April 28, 2016 by with 0 comment

UVA 11879 : Multiple of 17 - solution

#include<cstdio>
#include<string.h>
using namespace std;

int main()
{
    char n[111];
    while (scanf("%s",n)!=EOF)
    {
        int l=strlen(n);
        if (l==1 && n[0]=='0') return 0;
        int r=0;
        for (int i=0;i<l;i++)
        {
            r=r*10+n[i]-'0';
            r=r%17;
        }
        if (r==0) printf("1\n");
        else printf("0\n");
    }
    return 0;
}
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Published April 28, 2016 by with 0 comment

UVA 10591: Happy Number -solution

#include<bits/stdc++.h>
using namespace std;

int happy(int n)
{
    int temp=n;
    bool visit[10000];
    memset(visit,false,10000);
    while (1)
    {
        int temp2=0;
        while (temp)
        {
        int a=temp%10;
        temp2+=a*a;
        temp/=10;
        }
        if (temp2==1) return 1;
        if (temp2==n) return 0;
        if (visit[temp2]) return 0;
        visit[temp2]=true;
        temp=temp2;
    }
}

int main()
{
    int t,c=1;
    scanf("%d",&t);
    while (t--)
    {
        int n;
        scanf("%d",&n);
        if (happy(n)) printf("Case #%d: %d is a Happy number.\n",c++,n);
        else printf("Case #%d: %d is an Unhappy number.\n",c++,n);
    }
    return 0;
}
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Wednesday, April 27, 2016

Published April 27, 2016 by with 0 comment

UVA 10235 - Simply Emirp : Solution

#include<bits/stdc++.h>
using namespace std;

bool mark[1000000];
void sieve()
{
    memset(mark,true,1000000);
    mark[1]=false;
    for (int i=4; i<1000000;i+=2)
        mark[i]=false;
    for (int i=3;i<1000;i+=2)
        if (mark[i])
            for (int j=i*i;j<1000000;j+=i*2)
                mark[j]=false;
    return;
}

int main()
{
    int n;
    sieve();
    while (scanf("%d",&n)==1)
    {
        int rev=0;
        int temp=n;
        while (temp)
        {
            rev=rev*10+temp%10;
            temp/=10;
        }
        if (mark[n])
        {
            if (mark[rev] && n!=rev) printf("%d is emirp.\n",n);
            else printf("%d is prime.\n",n);
        }
        else printf("%d is not prime.\n",n);
    }
    return 0;
}
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Monday, April 25, 2016

Published April 25, 2016 by with 0 comment

UVA 12503 : Robot Instructions -Solution

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int t;
    scanf("%d", &t);
    while(t--)
    {
        int n,a;
        scanf("%d",&n);
        int j=1, pos=0;
        int ins[105]={0};
        char s[10], b[5];
        for(int i=1; i<=n; i++)
        {
            scanf("%s",s);
            if (s[0]=='L') ins[i] = -1;
            else if (s[0]=='R') ins[i] = 1;
            else
            {
                scanf("%s %d", b, &a);
                ins[i] = ins[a];
            }
            pos+=ins[i];
        }
        printf("%d\n",pos);
    }
    return 0;
}
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Published April 25, 2016 by with 0 comment

UVA 11952: Arithmetic -Solution

#include<cstdio>
#include<string.h>
using namespace std;

char A[10],B[10],C[10];

int one ()
{
    int la=strlen(A);
    int lb=strlen(B);
    int lc=strlen(C);
    for (int i=0;i<la;i++) if (A[i]!='1') return 0;
    for (int i=0;i<lb;i++) if (B[i]!='1') return 0;
    for (int i=0;i<lc;i++) if (C[i]!='1') return 0;
    if (la+lb!=lc) return 0;
    return 1;
}
int lowestbase ()
{
    int base=0;
    int la=strlen(A);
    int lb=strlen(B);
    int lc=strlen(C);
    for (int i=0;i<la;i++) if (base<A[i]-'0') base=A[i]-'0';
    for (int i=0;i<lb;i++) if (base<B[i]-'0') base=B[i]-'0';
    for (int i=0;i<lc;i++) if (base<C[i]-'0') base=C[i]-'0';
    return base;
}

long long int convert(char s[],int base)
{
    long long int n=0;
    for (int i=0;s[i];i++)
    n=s[i]-'0'+n*base;
    return n;
}

int main()
{
    int t;
    scanf("%d",&t);
    while (t--)
    {
        scanf("%s + %s = %s",A,B,C);
        long long int a,b,c;
        if (one())
        {
            printf("1\n");
            continue;
        }
        int base=lowestbase();
        if (base) base++;
        else
        {
            printf("2\n");
            continue;
        }
        int i;
        for (i=base;i<19;i++)
        {
            a=convert(A,i);
            b=convert(B,i);
            c=convert(C,i);
            if (a+b==c)
            {
                printf("%d\n",i);
                i=111;
            }
        }
        if (i==19) printf("0\n");
    }
    return 0;
}
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Published April 25, 2016 by with 0 comment

UVA 11192 : Group Reverse -Solution

#include<cstdio>
#include<string.h>
using namespace std;

int main()
{
    int g;
    while (scanf("%d",&g)==1)
    {
        if (g==0) break;
        char s[110];
        getchar();
        scanf("%s",s);
        int l=strlen(s);
        int nchar=l/g;
        for (int i=1;i<=g;i++)
        {
            int j=i*nchar;
            int t=nchar;
            while (t--) printf("%c",s[--j]);
        }
        printf("\n");
    }
    return 0;
}
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Published April 25, 2016 by with 0 comment

UVA 11455. : Behold my quadrangle -Solution

#include<cstdio>
#include<algorithm>
using namespace std;

int main()
{
    int t;
    scanf("%d",&t);
    while (t--)
    {
        unsigned long long int s[4];
        for (int i=0;i<4;i++) scanf("%llu",&s[i]);
        sort(s,s+4);
        if (s[0]==s[1]&&s[1]==s[2]&&s[2]==s[3])
            printf("square\n");
        else if (s[0]==s[1] && s[2]==s[3])
            printf("rectangle\n");      
        else if (s[0]+s[1]+s[2]>=s[3])
            printf("quadrangle\n");
        else printf("banana\n");
    }
    return 0;
}
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