#include<stdio.h> int main() { int n,m,i,k,j,c,s; while(scanf("%d%d",&n,&m)==2) { s=0; printf("%d %d ",n,m); if(n>m) { k=m; m=n; n=k; } for(i=n;i<=m;i++) { c=1; j=i; while(j>1) { if(j%2==0)j=j/2; else j=(3*j)+1; c++; } if (c>=s) s=c; } printf("%d\n",s); } return 0; }
Wednesday, April 13, 2016
UVA 100-The 3n + 1 problem Solution
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Studying at Shahjalal University of Science and Technology, Sylhet.
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